Artix Linux Forum

The thing is that if I simply run ly form terminal it works, but if I run this script https://raw.githubusercontent.com/drozdowsky/ly-void/master/res/ly-runit-service/run with sudo ./run I get the segmentation fault

I think that maybe the script is wrong cause there are variables like $GETTY_ARGS, $BAUD_RATE, and $TERM_NAME which are never declared or initialized. Could it be the reason?

I think, you'd better run

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sudo /usr/bin/ly tty2 "${BAUD_RATE}" "${TERM_NAME}"

with properly set values

I tried to follow this by changing my script with that

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#!/bin/sh

tty=${PWD##*-}

[ -r conf ] && . ./conf

if [ -x /sbin/getty -o -x /bin/getty ]; then
	# busybox
	GETTY=getty
elif [ -x /sbin/agetty -o -x /bin/agetty ]; then
	# util-linux
	GETTY=agetty
fi

#exec setsid ${GETTY} ${GETTY_ARGS} -nl /usr/bin/ly tty7 "${BAUD_RATE}" "${TERM_NAME}"

exec /usr/bin/ly tty7 "${BAUD_RATE}˝ "${TERM_NAME}"

by setting BAUD_RATE to 38400 and TERM_NAME to "linux". Still nothing, tty1 starts by default and if I change to tty7 it gets in stuck.

I tried to reproduce and get it working with:

/etc/runit/sv/ly/run

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#!/bin/sh

tty=${PWD##*-}

[ -r conf ] && . ./conf

if [ -x /sbin/getty -o -x /bin/getty ]; then
	# busybox
	GETTY=getty
elif [ -x /sbin/agetty -o -x /bin/agetty ]; then
	# util-linux
	GETTY=agetty
fi

exec setsid ${GETTY} ${GETTY_ARGS} -nl /usr/bin/ly tty7 "38400" "linux"

Edited /etc/ly/config.ini:

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# tty in use
tty = 7

Then just enabled service

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ln -s /etc/runit/sv/ly /run/runit/service

and reboot

Thank you! It finally works! Meaning that it shows at startup, but if I type my password it doesn't log me in
I select i3, my username, type my password, press enter, and it shows on top "logged out".... Why?